Lim x → 4 √x² + 9 X + 1
Jawaban:
1
Penjelasan dengan langkah-langkah:
[tex] \lim_{x \to \: 4} \: \frac{ \sqrt{ {x}^{2} + 9} }{x + 1} [/tex]
[tex] = \frac{ \sqrt{4 {}^{2} + 9 } }{4 + 1} [/tex]
[tex] = \frac{ \sqrt{16 + 9} }{5} [/tex]
[tex] = \frac{ \sqrt{25} }{5} [/tex]
[tex] = \frac{5}{5} = 1[/tex]
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